Base | Representation |
---|---|
bin | 111110101011010000011111… |
… | …0001011100110010001011111 |
3 | 2200022000001112010102210002012 |
4 | 1331112200332023212101133 |
5 | 1034230022114101423203 |
6 | 5232305042255021435 |
7 | 224060221254301412 |
oct | 17526407613462137 |
9 | 2608001463383065 |
10 | 551303045342303 |
11 | 14a731343722871 |
12 | 519ba28250a87b |
13 | 1a8808670ac997 |
14 | 9a1d2d1859b79 |
15 | 43b09cd9d1bd8 |
hex | 1f5683e2e645f |
551303045342303 has 2 divisors, whose sum is σ = 551303045342304. Its totient is φ = 551303045342302.
The previous prime is 551303045342249. The next prime is 551303045342341. The reversal of 551303045342303 is 303243540303155.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-551303045342303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551303045342003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275651522671151 + 275651522671152.
It is an arithmetic number, because the mean of its divisors is an integer number (275651522671152).
Almost surely, 2551303045342303 is an apocalyptic number.
551303045342303 is a deficient number, since it is larger than the sum of its proper divisors (1).
551303045342303 is an equidigital number, since it uses as much as digits as its factorization.
551303045342303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 41.
Adding to 551303045342303 its reverse (303243540303155), we get a palindrome (854546585645458).
The spelling of 551303045342303 in words is "five hundred fifty-one trillion, three hundred three billion, forty-five million, three hundred forty-two thousand, three hundred three".
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