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551310041 is a prime number
BaseRepresentation
bin100000110111000…
…101001011011001
31102102101110012102
4200313011023121
52112113410131
6130412253145
716443025622
oct4067051331
91372343172
10551310041
11263222437
121347711b5
138a2ab879
1453310a49
15336011cb
hex20dc52d9

551310041 has 2 divisors, whose sum is σ = 551310042. Its totient is φ = 551310040.

The previous prime is 551310037. The next prime is 551310043. The reversal of 551310041 is 140013155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 547326025 + 3984016 = 23395^2 + 1996^2 .

It is a cyclic number.

It is not a de Polignac number, because 551310041 - 22 = 551310037 is a prime.

It is a super-2 number, since 2×5513100412 = 607885522614843362, which contains 22 as substring.

Together with 551310043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 551309995 and 551310022.

It is not a weakly prime, because it can be changed into another prime (551310043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275655020 + 275655021.

It is an arithmetic number, because the mean of its divisors is an integer number (275655021).

Almost surely, 2551310041 is an apocalyptic number.

It is an amenable number.

551310041 is a deficient number, since it is larger than the sum of its proper divisors (1).

551310041 is an equidigital number, since it uses as much as digits as its factorization.

551310041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 300, while the sum is 20.

The square root of 551310041 is about 23479.9923551947. The cubic root of 551310041 is about 819.9712665918.

Adding to 551310041 its reverse (140013155), we get a palindrome (691323196).

The spelling of 551310041 in words is "five hundred fifty-one million, three hundred ten thousand, forty-one".