Base | Representation |
---|---|
bin | 110011010110000101… |
… | …110010101110010011 |
3 | 12021022012112212001011 |
4 | 303112011302232103 |
5 | 1400402122402014 |
6 | 41154350151351 |
7 | 3661131411064 |
oct | 632605625623 |
9 | 167265485034 |
10 | 55131450259 |
11 | 214212a2636 |
12 | a8274b2557 |
13 | 5277c04222 |
14 | 295004c56b |
15 | 167a1147c4 |
hex | cd6172b93 |
55131450259 has 2 divisors, whose sum is σ = 55131450260. Its totient is φ = 55131450258.
The previous prime is 55131450223. The next prime is 55131450277. The reversal of 55131450259 is 95205413155.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55131450259 is a prime.
It is not a weakly prime, because it can be changed into another prime (55131451259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27565725129 + 27565725130.
It is an arithmetic number, because the mean of its divisors is an integer number (27565725130).
Almost surely, 255131450259 is an apocalyptic number.
55131450259 is a deficient number, since it is larger than the sum of its proper divisors (1).
55131450259 is an equidigital number, since it uses as much as digits as its factorization.
55131450259 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 135000, while the sum is 40.
The spelling of 55131450259 in words is "fifty-five billion, one hundred thirty-one million, four hundred fifty thousand, two hundred fifty-nine".
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