Base | Representation |
---|---|
bin | 110011010110000101… |
… | …110010101101101111 |
3 | 12021022012112211222211 |
4 | 303112011302231233 |
5 | 1400402122401343 |
6 | 41154350151251 |
7 | 3661131411013 |
oct | 632605625557 |
9 | 167265484884 |
10 | 55131450223 |
11 | 214212a2603 |
12 | a8274b2527 |
13 | 5277c041c5 |
14 | 295004c543 |
15 | 167a11479d |
hex | cd6172b6f |
55131450223 has 2 divisors, whose sum is σ = 55131450224. Its totient is φ = 55131450222.
The previous prime is 55131450221. The next prime is 55131450259. The reversal of 55131450223 is 32205413155.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55131450223 - 21 = 55131450221 is a prime.
It is a super-2 number, since 2×551314502232 (a number of 22 digits) contains 22 as substring.
Together with 55131450221, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55131450221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27565725111 + 27565725112.
It is an arithmetic number, because the mean of its divisors is an integer number (27565725112).
Almost surely, 255131450223 is an apocalyptic number.
55131450223 is a deficient number, since it is larger than the sum of its proper divisors (1).
55131450223 is an equidigital number, since it uses as much as digits as its factorization.
55131450223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 55131450223 its reverse (32205413155), we get a palindrome (87336863378).
The spelling of 55131450223 in words is "fifty-five billion, one hundred thirty-one million, four hundred fifty thousand, two hundred twenty-three".
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