Base | Representation |
---|---|
bin | 110011010110001011… |
… | …000011010000010101 |
3 | 12021022022010212220021 |
4 | 303112023003100111 |
5 | 1400403001004233 |
6 | 41154435505141 |
7 | 3661146211615 |
oct | 632613032025 |
9 | 167268125807 |
10 | 55132828693 |
11 | 21422054238 |
12 | a827a581b1 |
13 | 5278297777 |
14 | 29502caa45 |
15 | 167a2d7e2d |
hex | cd62c3415 |
55132828693 has 2 divisors, whose sum is σ = 55132828694. Its totient is φ = 55132828692.
The previous prime is 55132828631. The next prime is 55132828771. The reversal of 55132828693 is 39682823155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30715016049 + 24417812644 = 175257^2 + 156262^2 .
It is a cyclic number.
It is not a de Polignac number, because 55132828693 - 217 = 55132697621 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55132828693.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55132820693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27566414346 + 27566414347.
It is an arithmetic number, because the mean of its divisors is an integer number (27566414347).
Almost surely, 255132828693 is an apocalyptic number.
It is an amenable number.
55132828693 is a deficient number, since it is larger than the sum of its proper divisors (1).
55132828693 is an equidigital number, since it uses as much as digits as its factorization.
55132828693 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3110400, while the sum is 52.
The spelling of 55132828693 in words is "fifty-five billion, one hundred thirty-two million, eight hundred twenty-eight thousand, six hundred ninety-three".
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