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55134214301183 is a prime number
BaseRepresentation
bin11001000100100111011110…
…10000100010010111111111
321020012210001012011022120212
430202103233100202113333
524211304332330114213
6313132150340103035
714420213141054063
oct1442235720422777
9236183035138525
1055134214301183
111662731a699616
126225468994a7b
13249c198803cb4
14d88720035aa3
1565927a19b9a8
hex3224ef4225ff

55134214301183 has 2 divisors, whose sum is σ = 55134214301184. Its totient is φ = 55134214301182.

The previous prime is 55134214301059. The next prime is 55134214301207. The reversal of 55134214301183 is 38110341243155.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55134214301183 - 224 = 55134197523967 is a prime.

It is a super-4 number, since 4×551342143011834 (a number of 56 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55134214301183.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55134214301483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27567107150591 + 27567107150592.

It is an arithmetic number, because the mean of its divisors is an integer number (27567107150592).

Almost surely, 255134214301183 is an apocalyptic number.

55134214301183 is a deficient number, since it is larger than the sum of its proper divisors (1).

55134214301183 is an equidigital number, since it uses as much as digits as its factorization.

55134214301183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 41.

The spelling of 55134214301183 in words is "fifty-five trillion, one hundred thirty-four billion, two hundred fourteen million, three hundred one thousand, one hundred eighty-three".