Base | Representation |
---|---|
bin | 11001000100100111011110… |
… | …10000100010010111111111 |
3 | 21020012210001012011022120212 |
4 | 30202103233100202113333 |
5 | 24211304332330114213 |
6 | 313132150340103035 |
7 | 14420213141054063 |
oct | 1442235720422777 |
9 | 236183035138525 |
10 | 55134214301183 |
11 | 1662731a699616 |
12 | 6225468994a7b |
13 | 249c198803cb4 |
14 | d88720035aa3 |
15 | 65927a19b9a8 |
hex | 3224ef4225ff |
55134214301183 has 2 divisors, whose sum is σ = 55134214301184. Its totient is φ = 55134214301182.
The previous prime is 55134214301059. The next prime is 55134214301207. The reversal of 55134214301183 is 38110341243155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55134214301183 - 224 = 55134197523967 is a prime.
It is a super-4 number, since 4×551342143011834 (a number of 56 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 55134214301183.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55134214301483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27567107150591 + 27567107150592.
It is an arithmetic number, because the mean of its divisors is an integer number (27567107150592).
Almost surely, 255134214301183 is an apocalyptic number.
55134214301183 is a deficient number, since it is larger than the sum of its proper divisors (1).
55134214301183 is an equidigital number, since it uses as much as digits as its factorization.
55134214301183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 41.
The spelling of 55134214301183 in words is "fifty-five trillion, one hundred thirty-four billion, two hundred fourteen million, three hundred one thousand, one hundred eighty-three".
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