Base | Representation |
---|---|
bin | 10000000010111101010… |
… | …00001010010011000100 |
3 | 1221201010001212200101211 |
4 | 20001132220022103010 |
5 | 33013122402301012 |
6 | 1101141134301204 |
7 | 54555542401510 |
oct | 10013650122304 |
9 | 1851101780354 |
10 | 551343400132 |
11 | 1a2906a80998 |
12 | 8aa2b957804 |
13 | 3ccb730cb05 |
14 | 1c984131140 |
15 | e51d3dc6a7 |
hex | 805ea0a4c4 |
551343400132 has 24 divisors (see below), whose sum is σ = 1138257344000. Its totient is φ = 228667769280.
The previous prime is 551343400103. The next prime is 551343400151. The reversal of 551343400132 is 231004343155.
It is a super-2 number, since 2×5513434001322 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 551343400094 and 551343400103.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 317593257 + ... + 317594992.
Almost surely, 2551343400132 is an apocalyptic number.
It is an amenable number.
551343400132 is an abundant number, since it is smaller than the sum of its proper divisors (586913943868).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
551343400132 is a wasteful number, since it uses less digits than its factorization.
551343400132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 635188291 (or 635188289 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 551343400132 its reverse (231004343155), we get a palindrome (782347743287).
The spelling of 551343400132 in words is "five hundred fifty-one billion, three hundred forty-three million, four hundred thousand, one hundred thirty-two".
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