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551343400132 = 22731635188249
BaseRepresentation
bin10000000010111101010…
…00001010010011000100
31221201010001212200101211
420001132220022103010
533013122402301012
61101141134301204
754555542401510
oct10013650122304
91851101780354
10551343400132
111a2906a80998
128aa2b957804
133ccb730cb05
141c984131140
15e51d3dc6a7
hex805ea0a4c4

551343400132 has 24 divisors (see below), whose sum is σ = 1138257344000. Its totient is φ = 228667769280.

The previous prime is 551343400103. The next prime is 551343400151. The reversal of 551343400132 is 231004343155.

It is a super-2 number, since 2×5513434001322 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a junction number, because it is equal to n+sod(n) for n = 551343400094 and 551343400103.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 317593257 + ... + 317594992.

Almost surely, 2551343400132 is an apocalyptic number.

It is an amenable number.

551343400132 is an abundant number, since it is smaller than the sum of its proper divisors (586913943868).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

551343400132 is a wasteful number, since it uses less digits than its factorization.

551343400132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 635188291 (or 635188289 counting only the distinct ones).

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 551343400132 its reverse (231004343155), we get a palindrome (782347743287).

The spelling of 551343400132 in words is "five hundred fifty-one billion, three hundred forty-three million, four hundred thousand, one hundred thirty-two".

Divisors: 1 2 4 7 14 28 31 62 124 217 434 868 635188249 1270376498 2540752996 4446317743 8892635486 17785270972 19690835719 39381671438 78763342876 137835850033 275671700066 551343400132