Base | Representation |
---|---|
bin | 10000000010111101010… |
… | …00001010010011010111 |
3 | 1221201010001212200102112 |
4 | 20001132220022103113 |
5 | 33013122402301101 |
6 | 1101141134301235 |
7 | 54555542401535 |
oct | 10013650122327 |
9 | 1851101780375 |
10 | 551343400151 |
11 | 1a2906a80a05 |
12 | 8aa2b95781b |
13 | 3ccb730cb1b |
14 | 1c984131155 |
15 | e51d3dc6bb |
hex | 805ea0a4d7 |
551343400151 has 2 divisors, whose sum is σ = 551343400152. Its totient is φ = 551343400150.
The previous prime is 551343400103. The next prime is 551343400159. The reversal of 551343400151 is 151004343155.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-551343400151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551343400159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275671700075 + 275671700076.
It is an arithmetic number, because the mean of its divisors is an integer number (275671700076).
Almost surely, 2551343400151 is an apocalyptic number.
551343400151 is a deficient number, since it is larger than the sum of its proper divisors (1).
551343400151 is an equidigital number, since it uses as much as digits as its factorization.
551343400151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 551343400151 in words is "five hundred fifty-one billion, three hundred forty-three million, four hundred thousand, one hundred fifty-one".
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