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55134397457 is a prime number
BaseRepresentation
bin110011010110010001…
…000010010000010001
312021022102002120211122
4303112101002100101
51400403401204312
641154533252025
73661165434356
oct632621022021
9167272076748
1055134397457
1121422a25937
12a828494015
1352786c6829
1429505b862d
15167a4e7b72
hexcd6442411

55134397457 has 2 divisors, whose sum is σ = 55134397458. Its totient is φ = 55134397456.

The previous prime is 55134397421. The next prime is 55134397477. The reversal of 55134397457 is 75479343155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29225953936 + 25908443521 = 170956^2 + 160961^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55134397457 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55134397399 and 55134397408.

It is not a weakly prime, because it can be changed into another prime (55134397477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27567198728 + 27567198729.

It is an arithmetic number, because the mean of its divisors is an integer number (27567198729).

Almost surely, 255134397457 is an apocalyptic number.

It is an amenable number.

55134397457 is a deficient number, since it is larger than the sum of its proper divisors (1).

55134397457 is an equidigital number, since it uses as much as digits as its factorization.

55134397457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7938000, while the sum is 53.

The spelling of 55134397457 in words is "fifty-five billion, one hundred thirty-four million, three hundred ninety-seven thousand, four hundred fifty-seven".