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551414131 is a prime number
BaseRepresentation
bin100000110111011…
…110100101110011
31102102120201222121
4200313132211303
52112130223011
6130414415111
716443641242
oct4067364563
91372521877
10551414131
11263293664
12134801497
138a317068
145333a959
1533621e71
hex20dde973

551414131 has 2 divisors, whose sum is σ = 551414132. Its totient is φ = 551414130.

The previous prime is 551414093. The next prime is 551414141. The reversal of 551414131 is 131414155.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 551414131 - 221 = 549316979 is a prime.

It is a super-2 number, since 2×5514141312 = 608115087732970322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 551414096 and 551414105.

It is not a weakly prime, because it can be changed into another prime (551414141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275707065 + 275707066.

It is an arithmetic number, because the mean of its divisors is an integer number (275707066).

Almost surely, 2551414131 is an apocalyptic number.

551414131 is a deficient number, since it is larger than the sum of its proper divisors (1).

551414131 is an equidigital number, since it uses as much as digits as its factorization.

551414131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1200, while the sum is 25.

The square root of 551414131 is about 23482.2088185929. The cubic root of 551414131 is about 820.0228681903.

Adding to 551414131 its reverse (131414155), we get a palindrome (682828286).

The spelling of 551414131 in words is "five hundred fifty-one million, four hundred fourteen thousand, one hundred thirty-one".