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551444134103 is a prime number
BaseRepresentation
bin10000000011001001010…
…00011011100011010111
31221201101002102111102122
420001210220123203113
533013324144242403
61101155133330155
754561204541532
oct10014450334327
91851332374378
10551444134103
111a2958923905
128aa5963695b
134000214c705
141c993673a19
15e527189838
hex8064a1b8d7

551444134103 has 2 divisors, whose sum is σ = 551444134104. Its totient is φ = 551444134102.

The previous prime is 551444134067. The next prime is 551444134141. The reversal of 551444134103 is 301431444155.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551444134103 is a prime.

It is a super-2 number, since 2×5514441341032 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551444134603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275722067051 + 275722067052.

It is an arithmetic number, because the mean of its divisors is an integer number (275722067052).

Almost surely, 2551444134103 is an apocalyptic number.

551444134103 is a deficient number, since it is larger than the sum of its proper divisors (1).

551444134103 is an equidigital number, since it uses as much as digits as its factorization.

551444134103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 551444134103 its reverse (301431444155), we get a palindrome (852875578258).

The spelling of 551444134103 in words is "five hundred fifty-one billion, four hundred forty-four million, one hundred thirty-four thousand, one hundred three".