Base | Representation |
---|---|
bin | 101000000111111001010… |
… | …0111010001001110010001 |
3 | 201112011220220220000201021 |
4 | 1100033302213101032101 |
5 | 1210322210413434301 |
6 | 15421155452435441 |
7 | 1106260532453041 |
oct | 120176247211621 |
9 | 21464826800637 |
10 | 5514513421201 |
11 | 1836768077134 |
12 | 7508bb478b81 |
13 | 310029cc4b25 |
14 | 150c9232d721 |
15 | 986a25a28a1 |
hex | 503f29d1391 |
5514513421201 has 2 divisors, whose sum is σ = 5514513421202. Its totient is φ = 5514513421200.
The previous prime is 5514513421189. The next prime is 5514513421211. The reversal of 5514513421201 is 1021243154155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2949394064400 + 2565119356801 = 1717380^2 + 1601599^2 .
It is a cyclic number.
It is not a de Polignac number, because 5514513421201 - 219 = 5514512896913 is a prime.
It is not a weakly prime, because it can be changed into another prime (5514513421211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757256710600 + 2757256710601.
It is an arithmetic number, because the mean of its divisors is an integer number (2757256710601).
Almost surely, 25514513421201 is an apocalyptic number.
It is an amenable number.
5514513421201 is a deficient number, since it is larger than the sum of its proper divisors (1).
5514513421201 is an equidigital number, since it uses as much as digits as its factorization.
5514513421201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 5514513421201 its reverse (1021243154155), we get a palindrome (6535756575356).
The spelling of 5514513421201 in words is "five trillion, five hundred fourteen billion, five hundred thirteen million, four hundred twenty-one thousand, two hundred one".
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