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5514913108373 is a prime number
BaseRepresentation
bin101000001000000101001…
…1011111101000110010101
3201112012221202222020102212
41100100022123331012111
51210324020223431443
615421303251243205
71106303454652544
oct120201233750625
921465852866385
105514913108373
111836952749009
127509b12a9505
13310091a56c06
14150ccd45215b
15986c7703618
hex5040a6fd195

5514913108373 has 2 divisors, whose sum is σ = 5514913108374. Its totient is φ = 5514913108372.

The previous prime is 5514913108351. The next prime is 5514913108379. The reversal of 5514913108373 is 3738013194155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4085661775204 + 1429251333169 = 2021302^2 + 1195513^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5514913108373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5514913108379) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757456554186 + 2757456554187.

It is an arithmetic number, because the mean of its divisors is an integer number (2757456554187).

Almost surely, 25514913108373 is an apocalyptic number.

It is an amenable number.

5514913108373 is a deficient number, since it is larger than the sum of its proper divisors (1).

5514913108373 is an equidigital number, since it uses as much as digits as its factorization.

5514913108373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 50.

The spelling of 5514913108373 in words is "five trillion, five hundred fourteen billion, nine hundred thirteen million, one hundred eight thousand, three hundred seventy-three".