Base | Representation |
---|---|
bin | 101000001000010100101… |
… | …0111011111101110111101 |
3 | 201112021021221102100111101 |
4 | 1100100221113133232331 |
5 | 1210331101100030323 |
6 | 15421430545453101 |
7 | 1106322355520134 |
oct | 120205127375675 |
9 | 21467257370441 |
10 | 5515432033213 |
11 | 1837099660a13 |
12 | 750b17041191 |
13 | 310145406c2b |
14 | 150d3c33291b |
15 | 98708058dad |
hex | 504295dfbbd |
5515432033213 has 2 divisors, whose sum is σ = 5515432033214. Its totient is φ = 5515432033212.
The previous prime is 5515432033171. The next prime is 5515432033217. The reversal of 5515432033213 is 3123302345155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4100957106724 + 1414474926489 = 2025082^2 + 1189317^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5515432033213 is a prime.
It is a super-3 number, since 3×55154320332133 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5515432033217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757716016606 + 2757716016607.
It is an arithmetic number, because the mean of its divisors is an integer number (2757716016607).
Almost surely, 25515432033213 is an apocalyptic number.
It is an amenable number.
5515432033213 is a deficient number, since it is larger than the sum of its proper divisors (1).
5515432033213 is an equidigital number, since it uses as much as digits as its factorization.
5515432033213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 5515432033213 its reverse (3123302345155), we get a palindrome (8638734378368).
The spelling of 5515432033213 in words is "five trillion, five hundred fifteen billion, four hundred thirty-two million, thirty-three thousand, two hundred thirteen".
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