Base | Representation |
---|---|
bin | 11001000101010010101110… |
… | …00100000010111110011011 |
3 | 21020021222222011220021000121 |
4 | 30202221113010002332123 |
5 | 24212144404224200122 |
6 | 313150550204014111 |
7 | 14421664360123642 |
oct | 1442512704027633 |
9 | 236258864807017 |
10 | 55157430693787 |
11 | 16636153747a44 |
12 | 6229a67b31337 |
13 | 24a1428669906 |
14 | d898c3572359 |
15 | 659b884a2bc7 |
hex | 322a57102f9b |
55157430693787 has 2 divisors, whose sum is σ = 55157430693788. Its totient is φ = 55157430693786.
The previous prime is 55157430693733. The next prime is 55157430693901. The reversal of 55157430693787 is 78739603475155.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55157430693787 is a prime.
It is a super-3 number, since 3×551574306937873 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (55157430696787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27578715346893 + 27578715346894.
It is an arithmetic number, because the mean of its divisors is an integer number (27578715346894).
Almost surely, 255157430693787 is an apocalyptic number.
55157430693787 is a deficient number, since it is larger than the sum of its proper divisors (1).
55157430693787 is an equidigital number, since it uses as much as digits as its factorization.
55157430693787 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 666792000, while the sum is 70.
The spelling of 55157430693787 in words is "fifty-five trillion, one hundred fifty-seven billion, four hundred thirty million, six hundred ninety-three thousand, seven hundred eighty-seven".
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