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55157430693901 is a prime number
BaseRepresentation
bin11001000101010010101110…
…00100000011000000001101
321020021222222011220021011211
430202221113010003000031
524212144404224201101
6313150550204014421
714421664360124164
oct1442512704030015
9236258864807154
1055157430693901
1116636153748038
126229a67b31411
1324a1428669993
14d898c35723db
15659b884a2c51
hex322a5710300d

55157430693901 has 2 divisors, whose sum is σ = 55157430693902. Its totient is φ = 55157430693900.

The previous prime is 55157430693787. The next prime is 55157430693907. The reversal of 55157430693901 is 10939603475155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50409503001225 + 4747927692676 = 7099965^2 + 2178974^2 .

It is a cyclic number.

It is not a de Polignac number, because 55157430693901 - 221 = 55157428596749 is a prime.

It is a super-3 number, since 3×551574306939013 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55157430693907) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27578715346950 + 27578715346951.

It is an arithmetic number, because the mean of its divisors is an integer number (27578715346951).

Almost surely, 255157430693901 is an apocalyptic number.

It is an amenable number.

55157430693901 is a deficient number, since it is larger than the sum of its proper divisors (1).

55157430693901 is an equidigital number, since it uses as much as digits as its factorization.

55157430693901 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15309000, while the sum is 58.

The spelling of 55157430693901 in words is "fifty-five trillion, one hundred fifty-seven billion, four hundred thirty million, six hundred ninety-three thousand, nine hundred one".