Base | Representation |
---|---|
bin | 11001000101101010100001… |
… | …00000000111000000011111 |
3 | 21020100012221110222020202012 |
4 | 30202311100200013000133 |
5 | 24212402040102333321 |
6 | 313200501552421435 |
7 | 14422626060233033 |
oct | 1442652040070037 |
9 | 236305843866665 |
10 | 55170205511711 |
11 | 166406097aa804 |
12 | 623043224787b |
13 | 24a26b31a8284 |
14 | d8a3760421c3 |
15 | 65a184c7405b |
hex | 322d5080701f |
55170205511711 has 2 divisors, whose sum is σ = 55170205511712. Its totient is φ = 55170205511710.
The previous prime is 55170205511683. The next prime is 55170205511719. The reversal of 55170205511711 is 11711550207155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55170205511711 - 230 = 55169131769887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55170205511719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27585102755855 + 27585102755856.
It is an arithmetic number, because the mean of its divisors is an integer number (27585102755856).
Almost surely, 255170205511711 is an apocalyptic number.
55170205511711 is a deficient number, since it is larger than the sum of its proper divisors (1).
55170205511711 is an equidigital number, since it uses as much as digits as its factorization.
55170205511711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61250, while the sum is 41.
Adding to 55170205511711 its reverse (11711550207155), we get a palindrome (66881755718866).
The spelling of 55170205511711 in words is "fifty-five trillion, one hundred seventy billion, two hundred five million, five hundred eleven thousand, seven hundred eleven".
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