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551829193453 is a prime number
BaseRepresentation
bin10000000011110111001…
…01010100001011101101
31221202100220222112120001
420001323211110023231
533020121233142303
61101301250424301
754603561515536
oct10017345241355
91852326875501
10551829193453
111a303621467a
128ab46592091
1340063b5c695
141c9cc86968d
15e54ad9b31d
hex807b9542ed

551829193453 has 2 divisors, whose sum is σ = 551829193454. Its totient is φ = 551829193452.

The previous prime is 551829193423. The next prime is 551829193463. The reversal of 551829193453 is 354391928155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 462832581124 + 88996612329 = 680318^2 + 298323^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551829193453 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 551829193394 and 551829193403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551829193423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275914596726 + 275914596727.

It is an arithmetic number, because the mean of its divisors is an integer number (275914596727).

Almost surely, 2551829193453 is an apocalyptic number.

It is an amenable number.

551829193453 is a deficient number, since it is larger than the sum of its proper divisors (1).

551829193453 is an equidigital number, since it uses as much as digits as its factorization.

551829193453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5832000, while the sum is 55.

The spelling of 551829193453 in words is "five hundred fifty-one billion, eight hundred twenty-nine million, one hundred ninety-three thousand, four hundred fifty-three".