Search a number
-
+
55201301 is a prime number
BaseRepresentation
bin1101001010010…
…0111000010101
310211212111221122
43102210320111
5103112420201
65251053325
71240126511
oct322447025
9124774848
1055201301
1129183611
12165a1245
13b5899bc
14748d141
154ca5e1b
hex34a4e15

55201301 has 2 divisors, whose sum is σ = 55201302. Its totient is φ = 55201300.

The previous prime is 55201283. The next prime is 55201309. The reversal of 55201301 is 10310255.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43573201 + 11628100 = 6601^2 + 3410^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55201301 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 55201301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55201309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27600650 + 27600651.

It is an arithmetic number, because the mean of its divisors is an integer number (27600651).

Almost surely, 255201301 is an apocalyptic number.

It is an amenable number.

55201301 is a deficient number, since it is larger than the sum of its proper divisors (1).

55201301 is an equidigital number, since it uses as much as digits as its factorization.

55201301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 55201301 is about 7429.7578022436. The cubic root of 55201301 is about 380.7586436923.

Adding to 55201301 its reverse (10310255), we get a palindrome (65511556).

The spelling of 55201301 in words is "fifty-five million, two hundred one thousand, three hundred one".