Base | Representation |
---|---|
bin | 11001000111000111101100… |
… | …11001000001010011010011 |
3 | 21020112000002000002210102202 |
4 | 30203203312121001103103 |
5 | 24214212014211431233 |
6 | 313235454110033415 |
7 | 14426346600431414 |
oct | 1443436631012323 |
9 | 236460060083382 |
10 | 55220233311443 |
11 | 1665a851130142 |
12 | 623a0744a886b |
13 | 24a732692c635 |
14 | d8c96032b80b |
15 | 65b611caabe8 |
hex | 3238f66414d3 |
55220233311443 has 2 divisors, whose sum is σ = 55220233311444. Its totient is φ = 55220233311442.
The previous prime is 55220233311377. The next prime is 55220233311449. The reversal of 55220233311443 is 34411333202255.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55220233311443 - 212 = 55220233307347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55220233311397 and 55220233311406.
It is not a weakly prime, because it can be changed into another prime (55220233311449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27610116655721 + 27610116655722.
It is an arithmetic number, because the mean of its divisors is an integer number (27610116655722).
Almost surely, 255220233311443 is an apocalyptic number.
55220233311443 is a deficient number, since it is larger than the sum of its proper divisors (1).
55220233311443 is an equidigital number, since it uses as much as digits as its factorization.
55220233311443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 55220233311443 its reverse (34411333202255), we get a palindrome (89631566513698).
The spelling of 55220233311443 in words is "fifty-five trillion, two hundred twenty billion, two hundred thirty-three million, three hundred eleven thousand, four hundred forty-three".
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