Base | Representation |
---|---|
bin | 111110110001111100000111… |
… | …0001011111011000000011111 |
3 | 2200102020211212021100111102021 |
4 | 1331203320032023323000133 |
5 | 1034340043322424402312 |
6 | 5234250554140041011 |
7 | 224213451112525162 |
oct | 17543701613730037 |
9 | 2612224767314367 |
10 | 552221363122207 |
11 | 14aa55846112839 |
12 | 51b28249233167 |
13 | 1a919335880bbc |
14 | 9a5192994dad9 |
15 | 43c9829238c07 |
hex | 1f63e0e2fb01f |
552221363122207 has 2 divisors, whose sum is σ = 552221363122208. Its totient is φ = 552221363122206.
The previous prime is 552221363122109. The next prime is 552221363122337. The reversal of 552221363122207 is 702221363122255.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 552221363122207 - 215 = 552221363089439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (552221463122207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276110681561103 + 276110681561104.
It is an arithmetic number, because the mean of its divisors is an integer number (276110681561104).
Almost surely, 2552221363122207 is an apocalyptic number.
552221363122207 is a deficient number, since it is larger than the sum of its proper divisors (1).
552221363122207 is an equidigital number, since it uses as much as digits as its factorization.
552221363122207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 604800, while the sum is 43.
The spelling of 552221363122207 in words is "five hundred fifty-two trillion, two hundred twenty-one billion, three hundred sixty-three million, one hundred twenty-two thousand, two hundred seven".
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