Base | Representation |
---|---|
bin | 11001000111001011011101… |
… | …10101011010110101110011 |
3 | 21020112012021211102112012121 |
4 | 30203211232311122311303 |
5 | 24214230134012201003 |
6 | 313240430412535111 |
7 | 14426450635252015 |
oct | 1443455665326563 |
9 | 236465254375177 |
10 | 55222254022003 |
11 | 16660698832972 |
12 | 623a539181497 |
13 | 24a7589478663 |
14 | d8cab28581b5 |
15 | 65b6ce3aecbd |
hex | 32396ed5ad73 |
55222254022003 has 2 divisors, whose sum is σ = 55222254022004. Its totient is φ = 55222254022002.
The previous prime is 55222254021929. The next prime is 55222254022051. The reversal of 55222254022003 is 30022045222255.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55222254022003 - 225 = 55222220467571 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55222254022003.
It is not a weakly prime, because it can be changed into another prime (55222254022703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27611127011001 + 27611127011002.
It is an arithmetic number, because the mean of its divisors is an integer number (27611127011002).
Almost surely, 255222254022003 is an apocalyptic number.
55222254022003 is a deficient number, since it is larger than the sum of its proper divisors (1).
55222254022003 is an equidigital number, since it uses as much as digits as its factorization.
55222254022003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96000, while the sum is 34.
Adding to 55222254022003 its reverse (30022045222255), we get a palindrome (85244299244258).
The spelling of 55222254022003 in words is "fifty-five trillion, two hundred twenty-two billion, two hundred fifty-four million, twenty-two thousand, three".
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