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552241433 is a prime number
BaseRepresentation
bin100000111010101…
…000100100011001
31102111010202211102
4200322220210121
52112333211213
6130444241145
716453655222
oct4072504431
91374122742
10552241433
112637a9187
12134b401b5
138a5467a3
14534b4249
1533737158
hex20ea8919

552241433 has 2 divisors, whose sum is σ = 552241434. Its totient is φ = 552241432.

The previous prime is 552241429. The next prime is 552241451. The reversal of 552241433 is 334142255.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 527758729 + 24482704 = 22973^2 + 4948^2 .

It is a cyclic number.

It is not a de Polignac number, because 552241433 - 22 = 552241429 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 552241396 and 552241405.

It is not a weakly prime, because it can be changed into another prime (552241463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276120716 + 276120717.

It is an arithmetic number, because the mean of its divisors is an integer number (276120717).

Almost surely, 2552241433 is an apocalyptic number.

It is an amenable number.

552241433 is a deficient number, since it is larger than the sum of its proper divisors (1).

552241433 is an equidigital number, since it uses as much as digits as its factorization.

552241433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 29.

The square root of 552241433 is about 23499.8177226973. The cubic root of 552241433 is about 820.4327643258.

Adding to 552241433 its reverse (334142255), we get a palindrome (886383688).

The spelling of 552241433 in words is "five hundred fifty-two million, two hundred forty-one thousand, four hundred thirty-three".