Base | Representation |
---|---|
bin | 111110110010100010010011… |
… | …1111110010111000100111011 |
3 | 2200102112200121120111110220002 |
4 | 1331211010213332113010323 |
5 | 1034342414330414402103 |
6 | 5234352402422223215 |
7 | 224222414061013223 |
oct | 17545044776270473 |
9 | 2612480546443802 |
10 | 552303400153403 |
11 | 14aa87613959578 |
12 | 51b40123284b0b |
13 | 1a923caaa27502 |
14 | 9a558ad063083 |
15 | 43cba2b482488 |
hex | 1f65127f9713b |
552303400153403 has 2 divisors, whose sum is σ = 552303400153404. Its totient is φ = 552303400153402.
The previous prime is 552303400153399. The next prime is 552303400153423. The reversal of 552303400153403 is 304351004303255.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 552303400153403 - 22 = 552303400153399 is a prime.
It is not a weakly prime, because it can be changed into another prime (552303400153423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276151700076701 + 276151700076702.
It is an arithmetic number, because the mean of its divisors is an integer number (276151700076702).
Almost surely, 2552303400153403 is an apocalyptic number.
552303400153403 is a deficient number, since it is larger than the sum of its proper divisors (1).
552303400153403 is an equidigital number, since it uses as much as digits as its factorization.
552303400153403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324000, while the sum is 38.
Adding to 552303400153403 its reverse (304351004303255), we get a palindrome (856654404456658).
The spelling of 552303400153403 in words is "five hundred fifty-two trillion, three hundred three billion, four hundred million, one hundred fifty-three thousand, four hundred three".
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