Base | Representation |
---|---|
bin | 11001001000000001011000… |
… | …01110101110010101111011 |
3 | 21020121222000012221022021221 |
4 | 30210000230032232111323 |
5 | 24220213430021244313 |
6 | 313302015042412511 |
7 | 14431524163435201 |
oct | 1444005416562573 |
9 | 236558005838257 |
10 | 55251201353083 |
11 | 166719a284a18a |
12 | 6244077661137 |
13 | 24aa220722428 |
14 | d9025b165071 |
15 | 65c3258a1c8d |
hex | 32402c3ae57b |
55251201353083 has 2 divisors, whose sum is σ = 55251201353084. Its totient is φ = 55251201353082.
The previous prime is 55251201353081. The next prime is 55251201353123. The reversal of 55251201353083 is 38035310215255.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55251201353083 - 21 = 55251201353081 is a prime.
Together with 55251201353081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (55251201353081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27625600676541 + 27625600676542.
It is an arithmetic number, because the mean of its divisors is an integer number (27625600676542).
Almost surely, 255251201353083 is an apocalyptic number.
55251201353083 is a deficient number, since it is larger than the sum of its proper divisors (1).
55251201353083 is an equidigital number, since it uses as much as digits as its factorization.
55251201353083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540000, while the sum is 43.
The spelling of 55251201353083 in words is "fifty-five trillion, two hundred fifty-one billion, two hundred one million, three hundred fifty-three thousand, eighty-three".
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