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55280720993 is a prime number
BaseRepresentation
bin110011011110111111…
…001101110001100001
312021200121102120222212
4303132333031301201
51401203331032433
641221241411505
73664623242531
oct633677156141
9167617376885
1055280720993
1121498586983
12a869499b95
13529cb091c4
142965bc74c1
15168829cd48
hexcdefcdc61

55280720993 has 2 divisors, whose sum is σ = 55280720994. Its totient is φ = 55280720992.

The previous prime is 55280720981. The next prime is 55280721043. The reversal of 55280720993 is 39902708255.

It is an a-pointer prime, because the next prime (55280721043) can be obtained adding 55280720993 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 46901698624 + 8379022369 = 216568^2 + 91537^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55280720993 is a prime.

It is a super-2 number, since 2×552807209932 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (55280720903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27640360496 + 27640360497.

It is an arithmetic number, because the mean of its divisors is an integer number (27640360497).

Almost surely, 255280720993 is an apocalyptic number.

It is an amenable number.

55280720993 is a deficient number, since it is larger than the sum of its proper divisors (1).

55280720993 is an equidigital number, since it uses as much as digits as its factorization.

55280720993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 50.

The spelling of 55280720993 in words is "fifty-five billion, two hundred eighty million, seven hundred twenty thousand, nine hundred ninety-three".