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55300151319989 is a prime number
BaseRepresentation
bin11001001001011100100011…
…11000000001110110110101
321020210122100121221021022012
430210232101320001312311
524222014202214214424
6313340312214214005
714435206205334032
oct1444562170016665
9236718317837265
1055300151319989
1116690731825894
126251658954305
1324b1a21a877a4
14d92782242389
1565d73ce80b0e
hex324b91e01db5

55300151319989 has 2 divisors, whose sum is σ = 55300151319990. Its totient is φ = 55300151319988.

The previous prime is 55300151319979. The next prime is 55300151320013. The reversal of 55300151319989 is 98991315100355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53263942186225 + 2036209133764 = 7298215^2 + 1426958^2 .

It is a cyclic number.

It is not a de Polignac number, because 55300151319989 - 244 = 37707965275573 is a prime.

It is a super-2 number, since 2×553001513199892 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55300151319979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27650075659994 + 27650075659995.

It is an arithmetic number, because the mean of its divisors is an integer number (27650075659995).

Almost surely, 255300151319989 is an apocalyptic number.

It is an amenable number.

55300151319989 is a deficient number, since it is larger than the sum of its proper divisors (1).

55300151319989 is an equidigital number, since it uses as much as digits as its factorization.

55300151319989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6561000, while the sum is 59.

The spelling of 55300151319989 in words is "fifty-five trillion, three hundred billion, one hundred fifty-one million, three hundred nineteen thousand, nine hundred eighty-nine".