Base | Representation |
---|---|
bin | 110011100000011100… |
… | …111110100010011001 |
3 | 12021202022200100012221 |
4 | 303200130332202121 |
5 | 1401231124100441 |
6 | 41223520304041 |
7 | 3665342203021 |
oct | 634034764231 |
9 | 167668610187 |
10 | 55305300121 |
11 | 21500444605 |
12 | a875772021 |
13 | 52a4c33976 |
14 | 2969184a81 |
15 | 168a5058d1 |
hex | ce073e899 |
55305300121 has 2 divisors, whose sum is σ = 55305300122. Its totient is φ = 55305300120.
The previous prime is 55305300107. The next prime is 55305300143. The reversal of 55305300121 is 12100350355.
55305300121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54587649600 + 717650521 = 233640^2 + 26789^2 .
It is a cyclic number.
It is not a de Polignac number, because 55305300121 - 27 = 55305299993 is a prime.
It is a super-2 number, since 2×553053001212 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55305300151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27652650060 + 27652650061.
It is an arithmetic number, because the mean of its divisors is an integer number (27652650061).
Almost surely, 255305300121 is an apocalyptic number.
It is an amenable number.
55305300121 is a deficient number, since it is larger than the sum of its proper divisors (1).
55305300121 is an equidigital number, since it uses as much as digits as its factorization.
55305300121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2250, while the sum is 25.
Adding to 55305300121 its reverse (12100350355), we get a palindrome (67405650476).
The spelling of 55305300121 in words is "fifty-five billion, three hundred five million, three hundred thousand, one hundred twenty-one".
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