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5531254463681 is a prime number
BaseRepresentation
bin101000001111101100001…
…1101010001110011000001
3201120210010122010002200122
41100133120131101303001
51211111002120314211
615433005003230025
71110422433124052
oct120373035216301
921523118102618
105531254463681
111842878a44131
12753bb1b18315
1331179745a61b
141519dd880729
1598d321766db
hex507d8751cc1

5531254463681 has 2 divisors, whose sum is σ = 5531254463682. Its totient is φ = 5531254463680.

The previous prime is 5531254463593. The next prime is 5531254463699. The reversal of 5531254463681 is 1863644521355.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2907567215281 + 2623687248400 = 1705159^2 + 1619780^2 .

It is a cyclic number.

It is not a de Polignac number, because 5531254463681 - 226 = 5531187354817 is a prime.

It is a super-2 number, since 2×55312544636812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5531254468681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2765627231840 + 2765627231841.

It is an arithmetic number, because the mean of its divisors is an integer number (2765627231841).

Almost surely, 25531254463681 is an apocalyptic number.

It is an amenable number.

5531254463681 is a deficient number, since it is larger than the sum of its proper divisors (1).

5531254463681 is an equidigital number, since it uses as much as digits as its factorization.

5531254463681 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368000, while the sum is 53.

The spelling of 5531254463681 in words is "five trillion, five hundred thirty-one billion, two hundred fifty-four million, four hundred sixty-three thousand, six hundred eighty-one".