Base | Representation |
---|---|
bin | 11001001001111000110001… |
… | …10000110011010010011011 |
3 | 21020212002110022102220200020 |
4 | 30210330120300303102123 |
5 | 24222241213102020410 |
6 | 313351255255041523 |
7 | 14436253452536163 |
oct | 1444743060632233 |
9 | 236762408386606 |
10 | 55315299251355 |
11 | 166970a53a6930 |
12 | 62545859702a3 |
13 | 24b3297159ca0 |
14 | d933bbd735a3 |
15 | 65dd27c66a70 |
hex | 324f18c3349b |
55315299251355 has 128 divisors (see below), whose sum is σ = 111514873236480. Its totient is φ = 23011003791360.
The previous prime is 55315299251351. The next prime is 55315299251363.
55315299251355 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55315299251355 - 22 = 55315299251351 is a prime.
It is not an unprimeable number, because it can be changed into a prime (55315299251351) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 10644364 + ... + 14964393.
It is an arithmetic number, because the mean of its divisors is an integer number (871209947160).
Almost surely, 255315299251355 is an apocalyptic number.
55315299251355 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55315299251355 is an abundant number, since it is smaller than the sum of its proper divisors (56199573985125).
55315299251355 is a wasteful number, since it uses less digits than its factorization.
55315299251355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25608861.
The product of its digits is 45562500, while the sum is 60.
The spelling of 55315299251355 in words is "fifty-five trillion, three hundred fifteen billion, two hundred ninety-nine million, two hundred fifty-one thousand, three hundred fifty-five".
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