Base | Representation |
---|---|
bin | 110011100001001101… |
… | …011010000011011111 |
3 | 12021210012120100100011 |
4 | 303201031122003133 |
5 | 1401242401330433 |
6 | 41225052344051 |
7 | 3665555130343 |
oct | 634115320337 |
9 | 167705510304 |
10 | 55317995743 |
11 | 21507625a5a |
12 | a879a75027 |
13 | 52a775a47a |
14 | 296ab2b623 |
15 | 168b6b23cd |
hex | ce135a0df |
55317995743 has 2 divisors, whose sum is σ = 55317995744. Its totient is φ = 55317995742.
The previous prime is 55317995737. The next prime is 55317995753. The reversal of 55317995743 is 34759971355.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55317995743 - 29 = 55317995231 is a prime.
It is a super-2 number, since 2×553179957432 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55317995713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27658997871 + 27658997872.
It is an arithmetic number, because the mean of its divisors is an integer number (27658997872).
Almost surely, 255317995743 is an apocalyptic number.
55317995743 is a deficient number, since it is larger than the sum of its proper divisors (1).
55317995743 is an equidigital number, since it uses as much as digits as its factorization.
55317995743 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17860500, while the sum is 58.
The spelling of 55317995743 in words is "fifty-five billion, three hundred seventeen million, nine hundred ninety-five thousand, seven hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •