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55321114627333 is a prime number
BaseRepresentation
bin11001001010000011100110…
…11000101100110100000101
321020212122110121002121210201
430211001303120230310011
524222340120321033313
6313354100314450501
714436550535450122
oct1445016330546405
9236778417077721
1055321114627333
1116699609a96985
126255729433a31
1324b39b2bc3269
14d937b0443749
1565e0685810dd
hex32507362cd05

55321114627333 has 2 divisors, whose sum is σ = 55321114627334. Its totient is φ = 55321114627332.

The previous prime is 55321114627279. The next prime is 55321114627393. The reversal of 55321114627333 is 33372641112355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51483523740804 + 3837590886529 = 7175202^2 + 1958977^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55321114627333 is a prime.

It is a super-2 number, since 2×553211146273332 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55321114627393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27660557313666 + 27660557313667.

It is an arithmetic number, because the mean of its divisors is an integer number (27660557313667).

Almost surely, 255321114627333 is an apocalyptic number.

It is an amenable number.

55321114627333 is a deficient number, since it is larger than the sum of its proper divisors (1).

55321114627333 is an equidigital number, since it uses as much as digits as its factorization.

55321114627333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1360800, while the sum is 46.

Adding to 55321114627333 its reverse (33372641112355), we get a palindrome (88693755739688).

The spelling of 55321114627333 in words is "fifty-five trillion, three hundred twenty-one billion, one hundred fourteen million, six hundred twenty-seven thousand, three hundred thirty-three".