Base | Representation |
---|---|
bin | 11001001010011001110100… |
… | …11101010011100010011101 |
3 | 21020220210021000010122111212 |
4 | 30211030322131103202131 |
5 | 24223034033333410401 |
6 | 313403352155554205 |
7 | 14440452265236566 |
oct | 1445147235234235 |
9 | 236823230118455 |
10 | 55333044435101 |
11 | 166a3681066044 |
12 | 6257ab875b965 |
13 | 24b4b6464c904 |
14 | d941c29cd16d |
15 | 65e515a88dbb |
hex | 32533a75389d |
55333044435101 has 2 divisors, whose sum is σ = 55333044435102. Its totient is φ = 55333044435100.
The previous prime is 55333044435089. The next prime is 55333044435167. The reversal of 55333044435101 is 10153444033355.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52493647562500 + 2839396872601 = 7245250^2 + 1685051^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55333044435101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55333044435901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27666522217550 + 27666522217551.
It is an arithmetic number, because the mean of its divisors is an integer number (27666522217551).
Almost surely, 255333044435101 is an apocalyptic number.
It is an amenable number.
55333044435101 is a deficient number, since it is larger than the sum of its proper divisors (1).
55333044435101 is an equidigital number, since it uses as much as digits as its factorization.
55333044435101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 55333044435101 its reverse (10153444033355), we get a palindrome (65486488468456).
The spelling of 55333044435101 in words is "fifty-five trillion, three hundred thirty-three billion, forty-four million, four hundred thirty-five thousand, one hundred one".
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