Base | Representation |
---|---|
bin | 10000000110101011100… |
… | …00011001111111111101 |
3 | 1221220021100200122000011 |
4 | 20003111300121333331 |
5 | 33031221031102201 |
6 | 1102111332303221 |
7 | 54656221552105 |
oct | 10032560317775 |
9 | 1856240618004 |
10 | 553342050301 |
11 | 1a3742186397 |
12 | 8b2a9171b11 |
13 | 40245403951 |
14 | 1cad3758205 |
15 | e5d8ad5151 |
hex | 80d5c19ffd |
553342050301 has 2 divisors, whose sum is σ = 553342050302. Its totient is φ = 553342050300.
The previous prime is 553342050221. The next prime is 553342050319. The reversal of 553342050301 is 103050243355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 552338808025 + 1003242276 = 743195^2 + 31674^2 .
It is a cyclic number.
It is not a de Polignac number, because 553342050301 - 211 = 553342048253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (553342050101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276671025150 + 276671025151.
It is an arithmetic number, because the mean of its divisors is an integer number (276671025151).
Almost surely, 2553342050301 is an apocalyptic number.
It is an amenable number.
553342050301 is a deficient number, since it is larger than the sum of its proper divisors (1).
553342050301 is an equidigital number, since it uses as much as digits as its factorization.
553342050301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 553342050301 its reverse (103050243355), we get a palindrome (656392293656).
The spelling of 553342050301 in words is "five hundred fifty-three billion, three hundred forty-two million, fifty thousand, three hundred one".
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