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553342300141 is a prime number
BaseRepresentation
bin10000000110101011100…
…01010110111111101101
31221220021101011022201111
420003111301112333231
533031221112101031
61102111341512021
754656223642361
oct10032561267755
91856241138644
10553342300141
111a3742337074
128b2a9272611
1340245490597
141cad37c12a1
15e5d8b341b1
hex80d5c56fed

553342300141 has 2 divisors, whose sum is σ = 553342300142. Its totient is φ = 553342300140.

The previous prime is 553342300117. The next prime is 553342300201. The reversal of 553342300141 is 141003243355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 523554992041 + 29787308100 = 723571^2 + 172590^2 .

It is a cyclic number.

It is not a de Polignac number, because 553342300141 - 25 = 553342300109 is a prime.

It is a super-2 number, since 2×5533423001412 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (553342303141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276671150070 + 276671150071.

It is an arithmetic number, because the mean of its divisors is an integer number (276671150071).

Almost surely, 2553342300141 is an apocalyptic number.

It is an amenable number.

553342300141 is a deficient number, since it is larger than the sum of its proper divisors (1).

553342300141 is an equidigital number, since it uses as much as digits as its factorization.

553342300141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 553342300141 its reverse (141003243355), we get a palindrome (694345543496).

The spelling of 553342300141 in words is "five hundred fifty-three billion, three hundred forty-two million, three hundred thousand, one hundred forty-one".