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55334832013 is a prime number
BaseRepresentation
bin110011100010001101…
…101000011110001101
312021211101020201100201
4303202031220132031
51401311204111023
641230453253501
73666151211566
oct634215503615
9167741221321
1055334832013
112151608532a
12a883634291
1352ab0a3866
14296d07116d
15168cddabad
hexce236878d

55334832013 has 2 divisors, whose sum is σ = 55334832014. Its totient is φ = 55334832012.

The previous prime is 55334831983. The next prime is 55334832019. The reversal of 55334832013 is 31023843355.

55334832013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46871384004 + 8463448009 = 216498^2 + 91997^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55334832013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55334832019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27667416006 + 27667416007.

It is an arithmetic number, because the mean of its divisors is an integer number (27667416007).

Almost surely, 255334832013 is an apocalyptic number.

It is an amenable number.

55334832013 is a deficient number, since it is larger than the sum of its proper divisors (1).

55334832013 is an equidigital number, since it uses as much as digits as its factorization.

55334832013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 37.

The spelling of 55334832013 in words is "fifty-five billion, three hundred thirty-four million, eight hundred thirty-two thousand, thirteen".