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5533515241481 is a prime number
BaseRepresentation
bin101000010000101111100…
…1101011101100000001001
3201120222222012011111210202
41100201133031131200021
51211130114400211411
615434021203421545
71110532444330013
oct120413715354011
921528865144722
105533515241481
111843829105a37
127545230848b5
13311a6794bc76
14151b75c1d1b3
1598e1589b83b
hex5085f35d809

5533515241481 has 2 divisors, whose sum is σ = 5533515241482. Its totient is φ = 5533515241480.

The previous prime is 5533515241447. The next prime is 5533515241487. The reversal of 5533515241481 is 1841425153355.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4917235290256 + 616279951225 = 2217484^2 + 785035^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5533515241481 is a prime.

It is a super-2 number, since 2×55335152414812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5533515241487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2766757620740 + 2766757620741.

It is an arithmetic number, because the mean of its divisors is an integer number (2766757620741).

Almost surely, 25533515241481 is an apocalyptic number.

It is an amenable number.

5533515241481 is a deficient number, since it is larger than the sum of its proper divisors (1).

5533515241481 is an equidigital number, since it uses as much as digits as its factorization.

5533515241481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440000, while the sum is 47.

The spelling of 5533515241481 in words is "five trillion, five hundred thirty-three billion, five hundred fifteen million, two hundred forty-one thousand, four hundred eighty-one".