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5533701132977 is a prime number
BaseRepresentation
bin101000010000110101001…
…0010100101001010110001
3201121000110010221202222222
41100201222102211022301
51211131004442223402
615434051444010425
71110540162353513
oct120415222451261
921530403852888
105533701132977
111843914031a76
12754575390a15
13311a97306634
14151b927abbb3
1598e26d6a7a2
hex5086a4a52b1

5533701132977 has 2 divisors, whose sum is σ = 5533701132978. Its totient is φ = 5533701132976.

The previous prime is 5533701132937. The next prime is 5533701133043. The reversal of 5533701132977 is 7792311073355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5523646859536 + 10054273441 = 2350244^2 + 100271^2 .

It is a cyclic number.

It is not a de Polignac number, because 5533701132977 - 210 = 5533701131953 is a prime.

It is a super-2 number, since 2×55337011329772 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5533701132907) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2766850566488 + 2766850566489.

It is an arithmetic number, because the mean of its divisors is an integer number (2766850566489).

Almost surely, 25533701132977 is an apocalyptic number.

It is an amenable number.

5533701132977 is a deficient number, since it is larger than the sum of its proper divisors (1).

5533701132977 is an equidigital number, since it uses as much as digits as its factorization.

5533701132977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4167450, while the sum is 53.

The spelling of 5533701132977 in words is "five trillion, five hundred thirty-three billion, seven hundred one million, one hundred thirty-two thousand, nine hundred seventy-seven".