Base | Representation |
---|---|
bin | 101000010001001010101… |
… | …0111110100000100010101 |
3 | 201121002022112000102021101 |
4 | 1100202111113310010111 |
5 | 1211134000011100023 |
6 | 15434251303550101 |
7 | 1110564120113104 |
oct | 120422527640425 |
9 | 21532275012241 |
10 | 5534423925013 |
11 | 1844155029365 |
12 | 75473745b331 |
13 | 311b80c95c29 |
14 | 151c2079a03b |
15 | 98e6a5411ad |
hex | 508955f4115 |
5534423925013 has 2 divisors, whose sum is σ = 5534423925014. Its totient is φ = 5534423925012.
The previous prime is 5534423925007. The next prime is 5534423925047. The reversal of 5534423925013 is 3105293244355.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3435918226129 + 2098505698884 = 1853623^2 + 1448622^2 .
It is a cyclic number.
It is not a de Polignac number, because 5534423925013 - 213 = 5534423916821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5534423725013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2767211962506 + 2767211962507.
It is an arithmetic number, because the mean of its divisors is an integer number (2767211962507).
Almost surely, 25534423925013 is an apocalyptic number.
It is an amenable number.
5534423925013 is a deficient number, since it is larger than the sum of its proper divisors (1).
5534423925013 is an equidigital number, since it uses as much as digits as its factorization.
5534423925013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944000, while the sum is 46.
The spelling of 5534423925013 in words is "five trillion, five hundred thirty-four billion, four hundred twenty-three million, nine hundred twenty-five thousand, thirteen".
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