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553453033253 is a prime number
BaseRepresentation
bin10000000110111000101…
…11110001011100100101
31221220120002112010222212
420003130113301130211
533031432434031003
61102130335133205
754662040106421
oct10033427613445
91856502463885
10553453033253
111a379989953a
128b31a374205
13402623c1533
141cb043a7b81
15e5e3708dd8
hex80dc5f1725

553453033253 has 2 divisors, whose sum is σ = 553453033254. Its totient is φ = 553453033252.

The previous prime is 553453033193. The next prime is 553453033261. The reversal of 553453033253 is 352330354355.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 312059656129 + 241393377124 = 558623^2 + 491318^2 .

It is a cyclic number.

It is not a de Polignac number, because 553453033253 - 210 = 553453032229 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 553453033253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (553453033453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276726516626 + 276726516627.

It is an arithmetic number, because the mean of its divisors is an integer number (276726516627).

Almost surely, 2553453033253 is an apocalyptic number.

It is an amenable number.

553453033253 is a deficient number, since it is larger than the sum of its proper divisors (1).

553453033253 is an equidigital number, since it uses as much as digits as its factorization.

553453033253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1215000, while the sum is 41.

The spelling of 553453033253 in words is "five hundred fifty-three billion, four hundred fifty-three million, thirty-three thousand, two hundred fifty-three".