Base | Representation |
---|---|
bin | 10000000110111001001… |
… | …00010110100111011111 |
3 | 1221220120022201200222012 |
4 | 20003130210112213133 |
5 | 33031434310044411 |
6 | 1102130533541435 |
7 | 54662110123466 |
oct | 10033444264737 |
9 | 1856508650865 |
10 | 553456331231 |
11 | 1a37a0741341 |
12 | 8b31b4a487b |
13 | 40262ca76bb |
14 | 1cb049c59dd |
15 | e5e3b5b18b |
hex | 80dc9169df |
553456331231 has 2 divisors, whose sum is σ = 553456331232. Its totient is φ = 553456331230.
The previous prime is 553456331203. The next prime is 553456331327. The reversal of 553456331231 is 132133654355.
553456331231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 553456331231 - 238 = 278578424287 is a prime.
It is a super-2 number, since 2×5534563312312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (553456331431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276728165615 + 276728165616.
It is an arithmetic number, because the mean of its divisors is an integer number (276728165616).
Almost surely, 2553456331231 is an apocalyptic number.
553456331231 is a deficient number, since it is larger than the sum of its proper divisors (1).
553456331231 is an equidigital number, since it uses as much as digits as its factorization.
553456331231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 486000, while the sum is 41.
Adding to 553456331231 its reverse (132133654355), we get a palindrome (685589985586).
The spelling of 553456331231 in words is "five hundred fifty-three billion, four hundred fifty-six million, three hundred thirty-one thousand, two hundred thirty-one".
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