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55351431301 is a prime number
BaseRepresentation
bin110011100011001100…
…111101000010000101
312021212112111001022011
4303203030331002011
51401324431300201
641232245134221
73666442255165
oct634314750205
9167775431264
1055351431301
1121524492651
12a8890ba371
1352b166611a
1429713525a5
15168e5b9151
hexce333d085

55351431301 has 2 divisors, whose sum is σ = 55351431302. Its totient is φ = 55351431300.

The previous prime is 55351431151. The next prime is 55351431307. The reversal of 55351431301 is 10313415355.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55212780676 + 138650625 = 234974^2 + 11775^2 .

It is a cyclic number.

It is not a de Polignac number, because 55351431301 - 213 = 55351423109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55351431307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27675715650 + 27675715651.

It is an arithmetic number, because the mean of its divisors is an integer number (27675715651).

Almost surely, 255351431301 is an apocalyptic number.

It is an amenable number.

55351431301 is a deficient number, since it is larger than the sum of its proper divisors (1).

55351431301 is an equidigital number, since it uses as much as digits as its factorization.

55351431301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 55351431301 its reverse (10313415355), we get a palindrome (65664846656).

The spelling of 55351431301 in words is "fifty-five billion, three hundred fifty-one million, four hundred thirty-one thousand, three hundred one".