Base | Representation |
---|---|
bin | 11001001011000000000010… |
… | …10110010111010011010101 |
3 | 21020222202012211221210021112 |
4 | 30211200001112113103111 |
5 | 24223403043123310202 |
6 | 313421024104224405 |
7 | 14442106563400106 |
oct | 1445400126272325 |
9 | 236882184853245 |
10 | 55353561150677 |
11 | 1670134a229129 |
12 | 625ba8376b105 |
13 | 24b6a840b2aba |
14 | d951ab77c3ad |
15 | 65ed16d70b52 |
hex | 3258015974d5 |
55353561150677 has 2 divisors, whose sum is σ = 55353561150678. Its totient is φ = 55353561150676.
The previous prime is 55353561150631. The next prime is 55353561150683. The reversal of 55353561150677 is 77605116535355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31210479449956 + 24143081700721 = 5586634^2 + 4913561^2 .
It is a cyclic number.
It is not a de Polignac number, because 55353561150677 - 212 = 55353561146581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55353561150607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27676780575338 + 27676780575339.
It is an arithmetic number, because the mean of its divisors is an integer number (27676780575339).
Almost surely, 255353561150677 is an apocalyptic number.
It is an amenable number.
55353561150677 is a deficient number, since it is larger than the sum of its proper divisors (1).
55353561150677 is an equidigital number, since it uses as much as digits as its factorization.
55353561150677 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 49612500, while the sum is 59.
The spelling of 55353561150677 in words is "fifty-five trillion, three hundred fifty-three billion, five hundred sixty-one million, one hundred fifty thousand, six hundred seventy-seven".
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