Base | Representation |
---|---|
bin | 110011100011110011… |
… | …000010100000101001 |
3 | 12021220020021021122112 |
4 | 303203303002200221 |
5 | 1401340010241314 |
6 | 41233243132105 |
7 | 3666623156612 |
oct | 634363024051 |
9 | 167806237575 |
10 | 55361415209 |
11 | 2152a091711 |
12 | a890514035 |
13 | 52b3750569 |
14 | 29727d0c09 |
15 | 16903dc43e |
hex | ce3cc2829 |
55361415209 has 2 divisors, whose sum is σ = 55361415210. Its totient is φ = 55361415208.
The previous prime is 55361415191. The next prime is 55361415211. The reversal of 55361415209 is 90251416355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48431685184 + 6929730025 = 220072^2 + 83245^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55361415209 is a prime.
Together with 55361415211, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (55361415289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27680707604 + 27680707605.
It is an arithmetic number, because the mean of its divisors is an integer number (27680707605).
Almost surely, 255361415209 is an apocalyptic number.
It is an amenable number.
55361415209 is a deficient number, since it is larger than the sum of its proper divisors (1).
55361415209 is an equidigital number, since it uses as much as digits as its factorization.
55361415209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 41.
The spelling of 55361415209 in words is "fifty-five billion, three hundred sixty-one million, four hundred fifteen thousand, two hundred nine".
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