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55390137678053 is a prime number
BaseRepresentation
bin11001001100000100001010…
…11110101111100011100101
321021010020121221010220012122
430212002011132233203211
524230003000221144203
6313445513350155325
714444543150632133
oct1446020536574345
9237106557126178
1055390137678053
1116715909779552
126266b91052b45
1324ba362b115c9
14d96c7b3cc753
15660c58015538
hex3260857af8e5

55390137678053 has 2 divisors, whose sum is σ = 55390137678054. Its totient is φ = 55390137678052.

The previous prime is 55390137678049. The next prime is 55390137678077. The reversal of 55390137678053 is 35087673109355.

55390137678053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31842342981604 + 23547794696449 = 5642902^2 + 4852607^2 .

It is a cyclic number.

It is not a de Polignac number, because 55390137678053 - 22 = 55390137678049 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55390137678023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27695068839026 + 27695068839027.

It is an arithmetic number, because the mean of its divisors is an integer number (27695068839027).

Almost surely, 255390137678053 is an apocalyptic number.

It is an amenable number.

55390137678053 is a deficient number, since it is larger than the sum of its proper divisors (1).

55390137678053 is an equidigital number, since it uses as much as digits as its factorization.

55390137678053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 71442000, while the sum is 62.

The spelling of 55390137678053 in words is "fifty-five trillion, three hundred ninety billion, one hundred thirty-seven million, six hundred seventy-eight thousand, fifty-three".