Base | Representation |
---|---|
bin | 110011100101101101… |
… | …011100000100000001 |
3 | 12021222110122102200111 |
4 | 303211231130010001 |
5 | 1401421214021231 |
6 | 41240350551321 |
7 | 4000462664515 |
oct | 634555340401 |
9 | 167873572614 |
10 | 55393501441 |
11 | 21546207563 |
12 | a89b208541 |
13 | 52ba2a5cb5 |
14 | 2976b84145 |
15 | 16931294b1 |
hex | ce5b5c101 |
55393501441 has 2 divisors, whose sum is σ = 55393501442. Its totient is φ = 55393501440.
The previous prime is 55393501421. The next prime is 55393501453. The reversal of 55393501441 is 14410539355.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28076353600 + 27317147841 = 167560^2 + 165279^2 .
It is a cyclic number.
It is not a de Polignac number, because 55393501441 - 211 = 55393499393 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55393501394 and 55393501403.
It is not a weakly prime, because it can be changed into another prime (55393501411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27696750720 + 27696750721.
It is an arithmetic number, because the mean of its divisors is an integer number (27696750721).
Almost surely, 255393501441 is an apocalyptic number.
It is an amenable number.
55393501441 is a deficient number, since it is larger than the sum of its proper divisors (1).
55393501441 is an equidigital number, since it uses as much as digits as its factorization.
55393501441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 40.
The spelling of 55393501441 in words is "fifty-five billion, three hundred ninety-three million, five hundred one thousand, four hundred forty-one".
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