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55399058156131 is a prime number
BaseRepresentation
bin11001001100010100110010…
…01011101010101001100011
321021011002122121121010122121
430212022121023222221203
524230124232341444011
6313453550451045111
714445310206510634
oct1446123113525143
9237132577533577
1055399058156131
1116719677095788
1262688605a0797
1324bb154c6acc1
14d9748602388b
156610cb234e71
hex3262992eaa63

55399058156131 has 2 divisors, whose sum is σ = 55399058156132. Its totient is φ = 55399058156130.

The previous prime is 55399058156089. The next prime is 55399058156147. The reversal of 55399058156131 is 13165185099355.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55399058156131 - 29 = 55399058155619 is a prime.

It is a super-2 number, since 2×553990581561312 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55399058156131.

It is not a weakly prime, because it can be changed into another prime (55399058159131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27699529078065 + 27699529078066.

It is an arithmetic number, because the mean of its divisors is an integer number (27699529078066).

Almost surely, 255399058156131 is an apocalyptic number.

55399058156131 is a deficient number, since it is larger than the sum of its proper divisors (1).

55399058156131 is an equidigital number, since it uses as much as digits as its factorization.

55399058156131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21870000, while the sum is 61.

The spelling of 55399058156131 in words is "fifty-five trillion, three hundred ninety-nine billion, fifty-eight million, one hundred fifty-six thousand, one hundred thirty-one".