55400117 has 2 divisors, whose sum is σ = 55400118. Its totient is φ = 55400116.

The previous prime is 55400099. The next prime is 55400129. The reversal of 55400117 is 71100455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38019556 + 17380561 = 6166^2 + 4169^2 .

It is a cyclic number.

It is not a de Polignac number, because 55400117 - 2⁶ = 55400053 is a prime.

It is a super-2 number, since 2×55400117² = 6138345927227378, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 55400092 and 55400101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55400167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27700058 + 27700059.

It is an arithmetic number, because the mean of its divisors is an integer number (27700059).

Almost surely, 2^55400117 is an apocalyptic number.

It is an amenable number.

55400117 is a deficient number, since it is larger than the sum of its proper divisors (1).

55400117 is an equidigital number, since it uses as much as digits as its factorization.

55400117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 700, while the sum is 23.

The square root of 55400117 is about 7443.1254859770. The cubic root of 55400117 is about 381.2152163195.

It can be divided in two parts, 55400 and 117, that multiplied together give a triangular number (6481800 = T₃₆₀₀).

The spelling of 55400117 in words is "fifty-five million, four hundred thousand, one hundred seventeen".