Base | Representation |
---|---|
bin | 11001001100011010111011… |
… | …00100100101100000100011 |
3 | 21021011102011020110201022021 |
4 | 30212031131210211200203 |
5 | 24230203004333214021 |
6 | 313455253431322311 |
7 | 14445454645433551 |
oct | 1446153544454043 |
9 | 237142136421267 |
10 | 55402353023011 |
11 | 16720007a43a65 |
12 | 626941bb20397 |
13 | 24bb55b773a87 |
14 | d976b9864bd1 |
15 | 661220621c41 |
hex | 32635d925823 |
55402353023011 has 2 divisors, whose sum is σ = 55402353023012. Its totient is φ = 55402353023010.
The previous prime is 55402353022949. The next prime is 55402353023021. The reversal of 55402353023011 is 11032035320455.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55402353023011 is a prime.
It is a super-2 number, since 2×554023530230112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55402353023021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27701176511505 + 27701176511506.
It is an arithmetic number, because the mean of its divisors is an integer number (27701176511506).
Almost surely, 255402353023011 is an apocalyptic number.
55402353023011 is a deficient number, since it is larger than the sum of its proper divisors (1).
55402353023011 is an equidigital number, since it uses as much as digits as its factorization.
55402353023011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 55402353023011 its reverse (11032035320455), we get a palindrome (66434388343466).
The spelling of 55402353023011 in words is "fifty-five trillion, four hundred two billion, three hundred fifty-three million, twenty-three thousand, eleven".
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