5540376343 has 2 divisors, whose sum is σ = 5540376344. Its totient is φ = 5540376342.

The previous prime is 5540376251. The next prime is 5540376377. The reversal of 5540376343 is 3436730455.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5540376343 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5540376296 and 5540376305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5540326343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2770188171 + 2770188172.

It is an arithmetic number, because the mean of its divisors is an integer number (2770188172).

Almost surely, 2^5540376343 is an apocalyptic number.

5540376343 is a deficient number, since it is larger than the sum of its proper divisors (1).

5540376343 is an equidigital number, since it uses as much as digits as its factorization.

5540376343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 453600, while the sum is 40.

The square root of 5540376343 is about 74433.7043482319. The cubic root of 5540376343 is about 1769.4831119674.

The spelling of 5540376343 in words is "five billion, five hundred forty million, three hundred seventy-six thousand, three hundred forty-three".